5a^2+4a+1=0

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Solution for 5a^2+4a+1=0 equation:


Simplifying
5a2 + 4a + 1 = 0

Reorder the terms:
1 + 4a + 5a2 = 0

Solving
1 + 4a + 5a2 = 0

Solving for variable 'a'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + 0.8a + a2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + 0.8a + -0.2 + a2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + 0.8a + a2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + 0.8a + a2 = 0 + -0.2
0.8a + a2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
0.8a + a2 = -0.2

The a term is 0.8a.  Take half its coefficient (0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
0.8a + 0.16 + a2 = -0.2 + 0.16

Reorder the terms:
0.16 + 0.8a + a2 = -0.2 + 0.16

Combine like terms: -0.2 + 0.16 = -0.04
0.16 + 0.8a + a2 = -0.04

Factor a perfect square on the left side:
(a + 0.4)(a + 0.4) = -0.04

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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